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4x^2-72x+260=0
a = 4; b = -72; c = +260;
Δ = b2-4ac
Δ = -722-4·4·260
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-32}{2*4}=\frac{40}{8} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+32}{2*4}=\frac{104}{8} =13 $
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